2c + 4 ≤ 14
Subtracting 4 on both sides 2c + 4 – 4 ≤ 14 – 4
2c ≤ 10
Dividing by 2 on both the sides
\(\frac{2c}{2}\) ≤ \(\frac{10}{2}\)
c ≤ 5
Since the solutions are whole numbers which are less than r equal to 5, the solution set is 0, 1, 2, 3, 4 and 5.