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in Algebra by (26.1k points)
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Solve the following inequations and represent the solution on the number line: 

(i) k > -5, k is an integer. 

(ii) -7 < y, y is a negative integer. 

(iii) -4 < x < 8, x is a natural number. 

(iv) 3m – 5 < 2m + 1, m is an integer.

1 Answer

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(i) k > -5, k is an integer. 

Since the solution belongs to the set of integers, the solution is -4, -3, -2, -1, 0,… It’s graph on number line is shown below.

(ii) -7 < y, y is a negative integer. 

-7 <

Since the solution set belongs to the set of negative integers, the solution is -7, -6, -5, -4, -3, -2, -1.

Its graph on the number line is shown below.

(iii) -4 < x < 8, x is a natural number. 

-4 < x <

Since the solution belongs to the set of natural numbers, the solution is 1, 2, 3, 4, 5, 6, 7 and 8. 

Its graph on number line is shown below.

(iv) 3m – 5 < 2m + 1, m is an integer. 

3m – 5 < 2m + 1 

Subtracting 1 on both the sides 

3m – 5 – 1 < 2m + 1 + 1 

3m – 6 < 2m 

Subtracting 2m on both the sides 3m- 6 – 2m < 2m -2m 

m – 6 < 0

Adding 6 on both the sides m – 6 + 6 < 0 + 6 

m <

Since the solution belongs to the set of integers, the solution is 6, 5, 4, 3, 2, 1, 0,-1,… 

Its graph on number line is shown below

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