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Show that (x + 2y)2 – (x – 2y)2 = 8xy.

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LHS = (x + 2y)2 – (x – 2y)2

= x2 + (2 (x) x (x) 2y) + (2y)2 – [x2 – (2 (x) x (x) 2y) + (2y)2]

= x2 + 4xy + 4y2 – [x2 – 4xy + 22y2]

= x2 + 4xy + 4y2 – x2 + 4xy – 4y2

= x2 – x2 + 4xy + 4xy + 4y2 – 4y2

= x2 (1 – 1) + xy (4 + 4) + y2 (4 – 4)

= 0x2 + 8xy + 0y2 

= 8xy 

= RHS

∴ (x + 2y)2 – (x – 2y)2 = 8xy

[∵ (a + b)2 = a2 + 2ab + b2 (a – b)2 = a2 – 2ab + b2]

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