# A motorcar of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km/h.

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A motorcar of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km/h. Its velocity is slowed down to 18 km/h in 4 s by an unbalanced external force. Calculate the acceleration and change in momentum. Also calculate the magnitude of the force required.

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Mass of the motor car, m = 1200 kg

Initial velocity of the motor car, u = 90 km/h = 25 m/s

Final velocity of the motor car, v = 18 km/h = 5 m/s

Time taken, t = 4 s

According to the first equation of motion: v = u + at

5 = 25 + a (4)

a = – 5 m/s2

Negative sign indicates that its a retarding motion i.e. velocity is decreasing.

Change in momentum = mv – mu = m (v – u)

= 1200 (5 – 25) = – 24000 kg m s -1

Force = Mass × Acceleration = 1200 × – 5 = – 6000 N

Acceleration of the motor car = – 5 m/s

Change in momentum of the motor car = – 24000 kg m s -1

Hence, the force required to decrease the velocity is 6000 N. (Negative sign indicates retardation, decrease in momentum and retarding force)