**Given,** mean μ = 8 and

variance σ^{2}* = *9 ⇒ σ = \(\sqrt9\) = 3

**Probability function is normal distribution whose variance σ**^{2 }and mean μ is

P(x,σ,μ) = \(\frac{1}{\sqrt{2\pi}\sigma}e^{-\frac{1}{2}\big(\frac{\mathrm{x}-\mu}{\sigma}\big)^2}\) , **x ∈ R**

**then probability function for given problem is**

P(x,σ,μ) = \(\frac{1}{3\sqrt{2\pi}}e^{-\frac{1}{2}\big(\frac{\mathrm{x}-8}{3}\big)^2}\)

= \(\frac{1}{3\sqrt{2\pi}}e^{-\frac{1}{18}(\mathrm{x}-8)^2}\) , **x** **∈ R**