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Using repeated subtracting method find HCF of the following:

36 and 80

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36 and 80

36 and 80 m = 80, n = 36

80 – 36 = 44, now n = 44, m = 36

Since n > m, we should do n m

44 – 36 = 8, now n = 8, m = 36

36 – 8 = 28

Similarly, processing, proceeding, we do repeated subtraction till m = n

28 – 8 = 20

20 – 8 = 12

12 – 8 = 4

8 – 4 = 4 now m = n = 4

∴ HCF is 4

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