(c) a3 + a2 – 3a – 2
Given, \(x+\frac{1}{x}=a\)
Now, x3 + x2 + \(\frac{1}{x^3}+\frac{1}{x^2}\) = \(\big(x^3+\frac{1}{x^3}\big)\)+ \(\big(x^2+\frac{1}{x^2}\big)\)
= \(\big(x+\frac{1}{x}\big)^3\) - 3\(\big(x+\frac{1}{x}\big)\) + \(\big(x+\frac{1}{x}\big)^2\) - 2
= a3 – 3a + a2 – 2 = a3 + a2 – 3a – 2.