Piece 1 of wood length = 4 m 50 cm ; 1m = 100 cm
∴ 4m 50 cm = 4 x 100 + 50 = 450 cm
Piece 2 of wood length = 6 m 30 cm = 6 x 100 + 30 = 630 cm
Now, we need to find the HCF of 450 & 630 by repeated subtraction method.
Let bigger number be m & smaller number be n
Therefore, m = 630 & n = 450
m – n = 630 – 450 = 180; now m = 450, n = 180
m – n = 450 – 180 = 270; now m = 180, n = 270
n – m = 270 – 180 = 90; now m = 180, n = 90
m – n = 180 – 90 = 90
∴ now m = n …90 is HCF
Answer:
Length of largest peice of wood to measure exactly the length of both pieces of wood is 90 cm