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(i) What is the difference between molarity and molality? 

(ii) The molarity of a solution of sulphuric acid is 1.35 M. Calculate its molality. (The density of acid solution is 1.02 g cm–3 ).

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(i) 

Molarity Molality
It is defined as the number of moles of the solute in 1 litter of the solution. It is defined as the number of moles of solute present in 1 kg of solvent.
It is affected by the change in temperature. It is not affected by the change in temperature.

(ii) Molarity = 1.35 M

Mass of 1 L solution = 1.35 × 98

= 132.3 g

Mass of 1 L solution = 1000 × 1.02

= 1020 g (∵ Density = 1.02 g cm–3 )

Mass of water in solution = 1020 – 132.3

= 887.7 g = 0.888 kg

Molality = \(\frac{number\,of\,moles\,of\,solute}{Mass\,of\,solvent\,in\,kg}\) = \(\frac{1.35}{0.888}\) = 1.52 m

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