Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
716 views
in Chemistry by (44.0k points)
closed by

If 4 g of NaOH dissolves in 36g of H2O, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1 g ml-1 )

1 Answer

+1 vote
by (45.9k points)
selected by
 
Best answer

\(X_{NaOH} =\frac{n_{NaOH}}{n_{NaOH}+n{H_2O}}\)

\(\frac{\frac{W_{NaOH}}{M_{NaOH}}}{\frac{W_{NaOH}}{M_{NaOH}}+\frac{W_{H_2O}}{M_{H_2O}}}\)

\(\frac{\frac{4}{40}}{\frac{4}{40}+\frac{36}{18}}\)

\(\frac{\frac{1}{10}}{\frac{1}{10}+2}\) = \(\frac{\frac{1}{10}}{\frac{21}{10}}\) = \(\frac{1}{10}\) x \(\frac{10}{21}\) = \(\frac{1}{21}\)

= 0.047

\(\because\) xNaOH + xH2O = 1

\(\therefore\) xH2O = 1 - 0.047 = 0.953

Mass of solution = 36 + 4 = 40g

Volume of solution = Mass x Specific gravity

= 40 x 1 = 40 ml

M = \(\frac{W_B}{M_B}\) x \(\frac{1000}{40}\) = 2.5 M

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...