# (a) How many significant figures are there in the following:  (i) 0.0026

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(a) How many significant figures are there in the following:

(i) 0.0026

(ii) 6.022 × 1013

(b) Calculate the number of carbon atoms is 34.20 g of C6H12O6.

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(a) (i) 0.0026 = 2.6 × 10–3

It has two significant figures.

(ii) 6.022 × 1013

It has four significant figures.

(b) Number of particles in a mole = 6.023 × 1023

Molecular mass of C6H12O6 = 180

Number of carbon atoms = 6

$\therefore$ 180 g of C6H12O6 contains

= 6 × 6.023 × 1023 carbon atoms

$\frac{6\times6.023\times10^{23}\times34.20}{180}$

= 6.866 × 1023 carbon atoms