(a) (i) 0.0026 = 2.6 × 10–3
It has two significant figures.
(ii) 6.022 × 1013
It has four significant figures.
(b) Number of particles in a mole = 6.023 × 1023
Molecular mass of C6H12O6 = 180
Number of carbon atoms = 6
\(\therefore\) 180 g of C6H12O6 contains
= 6 × 6.023 × 1023 carbon atoms
\(\frac{6\times6.023\times10^{23}\times34.20}{180}\)
= 6.866 × 1023 carbon atoms