Question

How many grams of Cl₂ are required to completely react with 0.4 g of H₂ to yield HCl? Also, calculate the amount of HCl formed.

Answer 1

Now, 2 g of H₂ react with 71g of Cl₂ to give 73 g of HCl 

So, 0.4 g of H₂ react with \(\frac{71}{2}\) × 0.4 

= 14. 2 g of Cl₂ 

∴ 14.2 g of Cl₂ react to give \(\frac{73\times0.4}{2}\) 

= 14.6 g of HCl

Therefore, 14.2 g of Cl₂ and 14.6 g HCl are required.