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A sample of NaNO3 weighing 0.38 g is placed in 50 mL volumetric flask. The flask is then filled with water to the mark on the neck. What is the molarity of the solution?

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Molarity of the solution = \(\frac{0.38\,g/85\,g\,mol^{-1}}{50/1000}\)

\(\frac{0.38}{85}\) x \(\frac{20}{1}\) mol

\(\frac{7.6}{85}\) = 0.0894 M

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