Question

The water level in a metric measuring cup is 0.75 L before the addition of a pebble weighting 150 g. The water level after submerging the pebble is 0.82 L Determine the density of the pebble.

Answer 1

Volume displaced by the pebble = 0.82 – 0.75

= 0.07 L

= 70 mL

Mass of the pebble = 150 g

\(\therefore\) Density of pebble = \(\frac{Mass}{Volume}\) = \(\frac{150}{70}\) = 2.14 g mL^-1