If logam = x, then log1/a (1/m) equals

Question

If log_am = x, then log_1/a (\(\frac{1}{m}\)) equals

(a) \(\frac{1}{x}\)

(b) –x 

(c) – \(\frac{1}{x}\)

(d) x

Answer 1

(d) x

log_am = x ⇒ ax = m 

log_1/a \(\frac{1}{m}\) = y ⇒ (\(\frac{1}{a}\))y = \(\frac{1}{m}\) ⇒ m = ay ⇒ ay = ax ⇒ y = x