Number of moles of dioxygen = \(\frac{70.6\,g}{32\,g\,mol^{-1}}\)
= 2.21 mol
Number of moles of neon = \(\frac{167.5\,g}{20\,g\,mol^{-1}}\)
= 8.375 mol
Mole fraction of dioxygen
= \(\frac{No.\,of\,moles\,of\,dioxygen}{No.\,of\,moles\,of\,dioxygen}\)
+ No. of moles of neon
= \(\frac{2.21}{2.21+8.375}\) = \(\frac{2.21}{10.585}\) = 0.21
Mole fraction of neon
= \(\frac{No.\,of\,moles\,of\,neon}{No.\,of\,moles\,of\,neon}\)
+ No. of moles of dioxygen
= \(\frac{8.375}{8.375 + 2.21}\) = \(\frac{8.375}{10.585}\) = 0.79
Partial pressure of gas (dioxygen)
= mole fraction of dioxygen x total pressure
= 0.21 x 25 (bar) = 5.25 bar
Partial pressure of neon
= mole fraction of neon x total pressure
= 0.79 x 25 (bar) 19.75 bar
