(c) 24
Using the formula logan xm = \(\frac{m}{n}\) loga x , we have
log√b a \(\text{log}_\sqrt[3]{c}\) b \(\text{log}_\sqrt[4]{c}\) c = \(\text{log}_{b^\frac{1}{2}}\) a \(\text{log}_{c^\frac{1}{3}}\) b \(\text{log}_{a^\frac{1}{4}}\)c
= 2 logba × 3 logcb × 4 logac
= 24 \(\frac{log\,a}{log\,b}\times\frac{log\,b}{log\,c}\times\frac{log\,c}{log\,a}\) = 24.