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In Fig. 2.13, PQ ⊥ RQ, PQ = 5 cm and QR = 5 cm. Then △ PQR is

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In Fig. 2.13, PQ ⊥ RQ, PQ = 5 cm and QR = 5 cm. Then △ PQR is

(A) a right triangle but not isosceles     (B) an isosceles right triangle

(C) isosceles but not a right triangle     (D) neither isosceles nor right triangle

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The correct answer is (B) an isosceles right triangle
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In Fig., PQ ⊥ RQ, PQ = 5 cm and QR = 5 cm. Then ∆ PQR is
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