Question

A balloon filled with an ideal gas is taken from the surface of the deep sea to a depth of 100 m. What will be its volume in terms of its original volume?

Answer 1

Pressure at the surface = 76 cm of Hg = 76 x 13∙6 cm of H₂O

= 10∙3 m of H₂O

\(\therefore\) Pressure at 100 m depth

= 100 + 10∙3 m = 110∙3

Applying Boyle’s law,

P₁V₁ (At surface) = P₂V₂ (At 100 m depth),

10∙3 m x V = 110∙3 x V₂

Or V₂ = 0∙ 093 V

= 9∙3 % of V