According to Boyle's law,
P1V1 = P2V2
Given P1 = 1 bar, V1 = 2.27 L
P2 = 0.2 bar, V2 =?
\(\therefore\) 1 x 2.27 = 0.2 x V2
V2 = \(\frac{1\times 2.27}{0.2}\) = 11.35 L
Since balloon bursts at 0.2 bar pressure, the volume of balloon should be less then 11.35 L.