Question

At 25°C and 760 mm of Hg pressure, a gas occupies 600 mL volume. What will be its pressure at a height where temperature is 10°O and volume of the gas is 640 mL.

Answer 1

P1 = 760 mm Hg V1 = 640 mL T1 = 25 + 273  = 298 K

P2 = ? V2 = 640 mL T2 = 10 + 273 = 283 K

According to Ideal gas equation,

\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)

P₂ = \(\frac{P_1V_1T_1}{T_1V_2}\) = \(\frac{760\,mm\,Hg\times600\,ml\times283K}{298\times640\,ml}\)

= 676.6 mm Hg