Energy E = -13.6 x \(\frac{z^2}{n^2}\)eV
For He+ z = 2
Value of n for first orbit = 1
\(\therefore\) E = -13.6 x \(\frac{(2)^2}{(1)^2}\)
= -54.4 eV
Radius of this orbit,
rn = \(\frac{52.9(n^2)}{z}\)
r1 = \(\frac{52.9\times1^2}{2}\)
= 26.45 pm
= 0.2645 Å