Given, Time period T = 2.0 × 10−10s
Frequency v = \(\frac{1}{T}\) = \(\frac{1}{2.0\times10^{-10}}\) = 5 x 109 Hz
wave length \(\lambda\) = \(\frac{c}{v}\) = \(\frac{3\times10^8m/s}{5\times10^9s^{-1}}\)
= 0.06 m
Wave number \((\bar v)\) = \(\frac{1}{\lambda}\)
= \(\frac{1}{0.06\,m}\)
= 16.67 m−1