Q Radius of nth Bohr orbit
rn = \(\frac{0.529n^2}{z}\)
For H-atom, z = 1,
For first orbit n = 1
(i) For He+ ion, z = 2, third orbit, n = 3
r3 = \(\frac{0.529\times(3)^2}{2}\)
= \(\frac{0.529\times9}{2}\)
= 2.380 Å
(ii) For Li2+ion, z = 3
Second orbit, n = 2
\(\therefore\) r2 = \(\frac{0.529\times(2)^2}{3}\)
= \(\frac{0.529\times4}{3}\)
= 0.7053 Å