The uncertainty in the speed is 2% i.e.
45 x \(\frac{2}{100}\) = 0.9 m/s
According to Heisenberg uncertainty,
∆x × m∆v = \(\frac{h}{4\pi}\)
\(\therefore\) ∆x = \(\frac{h}{4\pi m\Delta v}\)
= \(\frac{6.626\times10^{-34}Js}{4\times3.14\times40\times10^{-3}kg\times0.9m/s}\)
=1.46 × 10−33 m
This is nearly ~1018 times smaller than the diameter of a typical atomic nucleus.