Mass of wagon = 2000 kg
Uncertainty in position, ∆x = \(\pm\)10 m
According to Heisenberg uncertainty principle
∆x × ∆p = \(\frac{h}{4\pi}\)
∆x × m∆v = \(\frac{h}{4\pi}\)
or ∆x × ∆v = \(\frac{h}{4\pi m}\)
∆v = \(\frac{h}{4\pi m\Delta \mathrm{x}}\)
= \(\frac{6.626\times10^{-34}kgm^2s^{-1}}{4\times3.14\times(2000kg)\times(10m)}\)
= 2.636 × 10−39 ms−1