Let heights difference between A and B = H

**Given ****:****-**

t = T/3

t = 5T/6

As we know that, Time of Flight,

T = 2u Sinθ/g

**u Sinθ = gT/2 ****-****-****-****-****-****-****(****1****)**

**For A****,**

h = usinθ t - 1/2 gt²

h = usinθ × T/3 - gT²/18

h = gT²/6 - gT²/18

**h = 2gT²/18**

**For**** ****B****,**

h' = usinθ t - 1/gt²

h' = gT/2 × 5T/6 - 1/2 g 25T²/36

h' = 5gT²/12 - 25gT²/72

**h' = 5gT²/72**

Again,

H = h - h' = 2gT²/18 - 5gT²/72

H = (8gT² - 5gT²)/72

H = 3gT²/72

**H ****=**** ****gT²****/****2****4**