(a) Calculation of the wave number
\(\lambda\) = 5800 Å = 5800 × 10-10 m
\(\bar{v}\) = \(\frac{1}{\lambda}\) = \(\frac{1}{5800\times10^{-10}}\)
= 1.724 × 106 m−1
= 1.724 × 104 cm1
(b) Calculation of frequency (v)
v = \(\frac{c}{\lambda}\) = \(\frac{3\times10^8ms^{-1}}{5800\times10^{-10}m}\)
= 5.172 × 10−14 s−1