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If a = log12m and b = log18m, then (a-2b)/(b-2a) equals

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If a = log12m and b = log18m, then \(\frac{a-2b}{b-2a}\) equals

(a) log32 

(b) log23 

(c) 0 

(d) 1

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(a) log32

\(\frac{a-2b}{b-2a}\) = \(\frac{\text{log}_{12}\,m-\,2\text{log}_{18}\,m}{\text{log}_{18}\,m-\,2\text{log}_{12}\,m}\)

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