Question

Draw and explain the M.O. diagram of Boron molecule.

Answer 1

1. Electronic configuration of B = 1s² 2s² 2p³

2. Electronic configuration of B, =σ1s² σ*1s² σ2s² σ*2s² π2p_x¹ π2p_z¹

3. Bond order = \(\frac{N_b-N_a}{2}\) = \(\frac{6-4}{2}\) = 1

4. B₂ molecule has two unpaired electrons hence it is paramagnetic.