Weight of organic compound = 0.32 g
Weight of BaSO4 formed = 0.466 g
233 g of BaSO4 contains = 32 g of sulphate
0.466 g of BaSO4 contain = \(\frac{32}{233}\) x \(\frac{0.466}{2.32}\) x 100
= \(\frac{32}{233}\) x \(\frac{46.6}{0.32}\) = 19.999 g of sulphur
% of sulphur = 20 %