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What conclusion can be drawn from each part of Fig. 2.41, if (a) DB is the bisector of ∠ADC?

(b) BD bisects ∠ABC?

(c) DC is the bisector of ∠ADB, CA ⊥ DA and CB ⊥ DB?

Sarthaks Test For Class 7-12

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(a) ∠ADB = ∠CDB (b) ∠ABD = ∠CBD

(c) ∠ADC = ∠BDC, ∠CAD = 90°, ∠CBD = 90°

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