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in Trigonometry by (350 points)
edited by

Find the value of \(\frac{1}{sin10°} - 4\, sin70°.\)

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1 Answer

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by (48.0k points)
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sin(3 × 10°) = sin(30°) = \(\frac{1}{2}\)

⇒ 3 sin10° - 4 sin310° = \(\frac{1}{2}\)

⇒ 8 sin310° - 6 sin10° + 1 = 0

After solving this polynomial in sin10°, we get

⇒ sin10° = 0.17365

sin70° = sin(10° + 60°)

= sin10° cos60° + cos10° sin60°

= 0.17365 × \(\frac{1}{2}\) + 0.9848 × \(\frac{\sqrt3}{2}\)

= 0.086825 + 0.852868

= 0.93693

\(\frac{1}{sin 10°}\) - 4 sin70° = \(\frac{1}{0.17365} - 4(0.93693)\)

= 5.75871 - 3.74772

= 2.01099 (2.011 Approx)

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