x = 1 + 2^{1/6 }+ 2^{2/6} + 2^{3/6} + 2^{4/6} + 2^{5/6}

**Clearly, This is a Geometric Progression with **

**Common Difference (r) = 2**^{1/6}

**First Term (a) = 1**

**Number Of Terms (n) = 6**

**And since we know the formula for the sum of GP, which is:**

**S= a(r**^{n}-1)/r-1

**S = ((2**^{1/6})^{6} - 1)/2^{1/6}-1

**S(x) = 1/2**^{1/6}-1

**Now, We have to find,**

**(1+1/x)**^{30 }or (1 + 2^{1/6} -1)^{30}

^{= }(2^{1/6})^{30}

^{=} 2^{5}

**=32**