**Steps of construction:**

1. Draw a line segment BC of 3.6cm.

2. At the point B, draw ∠x BC of 60^{o}

3. With center B and radius 4.8cm, draw an arc which intersects XB at D.

4. Join DC

5. Draw the perpendicular bisector of DC which intersects DB at A.

6. Join AC

Hence Δ ABCis the required triangle