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Construct a ΔABC in which AB + AC = 5.6 cm, BC = 4.5 cm, AB − AC = 1.5 cm and ∠B= 45°.

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Steps of construction:

Step 1: Draw a line segment BC of 4.5  cm 

Step 2: At B, draw an angle XBC of 45o

Step 3: With center B and radius 5.6 , cm draw an arc which intersects BX at D.

Step 4: Join DC

Step 5: Draw the perpendicular bisector of DC which intersects BD at A.

Step 6: Join AC

Therefore Δ ABC is a required triangle.

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