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Construct a ΔABC in which BC = 3.4 cm, AB − AC = 1.5 cm and ∠B = 45°.

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Steps of construction:

Step 1: Draw a line segment BC of 3.5cm.

Step 2: At B, draw an angle XBC of 45o

Step 3: With center B and radius 1.5cm, draw an arc which intersects BX at D.

Step 4: Join DC

Step 5: Draw the perpendicular bisector of DC which intersects BD produced at A.

Step 6: Join AC

Therefore Δ ABC is the required triangle

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