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Let, V1 = 2 L


T1 = 23.4 °C or 296.4 K

T2 = 26.1 °C or 299.1 K

V2 be the volume at temperature T2

If the pressure remains constant, then apply Charle’s law:

V1/T1 = V2/T2

V2 = V1T2/T1 = 2 x 299.1 / 296.4

                       = 2.0182 L

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