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Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11.

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Steps of construction:

Step 1: Draw a line segment AB of 11cm.

Step 2: DrawDAB = Y = 30o and FBA = Z = 90o

Step 3: Draw the angle bisector of DAB and EBA which intersect each other at x

Step 4: Draw the perpendicular bisector XA and XB which intersect AB at Y and Z respectively.

Step 5: Join XY and XZ

Therefore ΔXYZ  is the required triangle

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