**Steps of construction:**

Step 1: Draw a line segment AB of 11cm.

Step 2: Draw∠DAB = ∠Y = 30^{o} and ∠FBA = ∠Z = 90^{o}

Step 3: Draw the angle bisector of ∠DAB and ∠EBA which intersect each other at x

Step 4: Draw the perpendicular bisector XA and XB which intersect AB at Y and Z respectively.

Step 5: Join XY and XZ

Therefore ΔXYZ is the required triangle