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4.0k views
in Trigonometry by (15 points)
edited by

Evaluate :

Tan 35° Tan 40° Tan 50° Tan 55°

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1 Answer

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by (44.5k points)

tan35°, tan40°, tan45°, tan50°, tan55°

We know that,

tan(90−θ) = cotθ and cotθ = \(\frac{1}{tanθ}\)

tan35° = tan(90°−55°) = cot55°

tan40° = tan(90°−50°) = cot50°

∴ tan35° tan40° tan45° tan50° tan55°

= =cot55° cot50° tan45° tan50° tan55°

= \(\frac{1}{tan55°}\) \(\frac{1}{tan50°}\) tan45° tan50° tan55°

= tan45°

= 1

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