tan35°, tan40°, tan45°, tan50°, tan55°
We know that,
tan(90−θ) = cotθ and cotθ = \(\frac{1}{tanθ}\)
tan35° = tan(90°−55°) = cot55°
tan40° = tan(90°−50°) = cot50°
∴ tan35° tan40° tan45° tan50° tan55°
= =cot55° cot50° tan45° tan50° tan55°
= \(\frac{1}{tan55°}\) \(\frac{1}{tan50°}\) tan45° tan50° tan55°
= tan45°
= 1