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+1 vote
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in Coordinate Geometry by (24.0k points)
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A straight line passes through the points (5, 0) and (0, 3). The length of the perpendicular from the point (4, 4) on the line is:

(a) \(\frac{\sqrt{17}}{2}\)

(b) \(\frac{\sqrt{17}}{2}\)

(c) \(\frac{15}{\sqrt{34}}\)

(d) \(\frac{17}{2}\)

1 Answer

+2 votes
by (23.6k points)
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Best answer

(b) \(\frac{\sqrt{17}}{2}\)

Equation of the line through the points (5, 0) and (0, 3) 

y – 0 = \(\frac{3-0}{0-5}\) (x - 5)

⇒ y = \(\frac{-3}{5}\)(x - 5)

⇒ 5y + 3x – 15 = 0 

∴ Distance of perpendicular from point (4, 4) on the line

 5y + 3x – 15 = 0 is \(\bigg|\frac{5\times4+3\times4-15}{\sqrt{5^2+3^2}}\bigg|\)

\(\frac{|20+12-15|}{\sqrt{25+9}{}}\) = \(\frac{17}{\sqrt{34}}\) units. = \(\frac{\sqrt{17}}{2}\) units.

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