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What is the sum of the series \(\frac{2}{3}\) + \(\frac{8}{9}\) + \(\frac{26}{27}\) + \(\frac{80}{81}\).....to n terms?

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The Series \(\frac{2}{3}\) + \(\frac{8}{9}\) + \(\frac{26}{27}\) + \(\frac{80}{81}\).....to n terms can be written as

\(\big(1-\frac{1}{3}\big)\) + \(\big(1-\frac{1}{9}\big)\) + \(\big(1-\frac{1}{27}\big)\) + \(\big(1-\frac{1}{81}\big)\) + ...... to n terms

= (1 + 1 + 1 + 1 + .... to n terms)- \(\bigg(\frac13+\frac19+\frac{1}{27}+\frac{1}{81}+....\text{to n terms}\bigg)\)

= n - \(\frac{\frac13\bigg(1-\big(\frac{1}{3}\big)^n\bigg)}{1-\frac13}\)                    \(\big(S_n = \frac{a(1-r^n)}{1-r}, \text{here}\,a=\frac{1}{3},\,r=\frac{1}{3}\big)\)

= n - \(\frac{\frac13\bigg(1-\frac{1}{3^n}\bigg)}{\frac23}\) = n - \(\frac{1}{2}(1-3^{-n}).\)

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