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Six positive numbers are in G.P. such that their product is 1000. If the fourth term is 1, then find the last term.

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Let the six numbers in G.P. be \(\frac{a}{r^5}\)\(\frac{a}{r^3}\)\(\frac{a}{r}\), ar, ar3, ar5.

Then, Product = 1000

⇒ \(\frac{a}{r^5}\) x \(\frac{a}{r^3}\) x \(\frac{a}{r}\) x ar x ar3 x ar5

⇒ a6 = 1000 ⇒ a = \(\sqrt{10}\)

Given, Fourth term = t4 = ar = 1

⇒ \(\sqrt{10}\) x r = 1 ⇒ \(\frac{1}{\sqrt{10}}\)

∴ Last term = ar5\(\sqrt{10}\) x\(\bigg(\)\(\frac{1}{\sqrt{10}}\)\(\bigg)\)\(\frac{1}{100}.\)

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