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Question

If the fourth term in the Binomial expansion of (2/x+ x^log5x)⁶ (x>0) is 20 x 8⁷, then a value of x is?

Answer 1

log₂​x=6

⇒x=2⁶=8²

log₂​x=−3

⇒x=2⁻³=8⁻¹.