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If the third term of a G.P. is 3, then the product of its first 5 terms is:

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If the third term of a G.P. is 3, then the product of its first 5 terms is:

(a) 15 

(b) 81 

(c) 243 

(d) Cannot be determined

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(c) 243

Let a and r be the first term and common ratio respectively of the given G.P. Then, 

T3 = ar2 = 3 

Required product = a . ar . ar2 . ar3 . ar4 

= a5 r15 = (ar3)5 = 35 = 243.

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