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Find the HCF of each set of numbers using prime factorisation method.

(i) 18, 24

(ii) 51, 85

(iii) 61, 76

(iv) 84, 120

(v) 27, 45, 81

(vi) 45, 55, 95

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(i) 18, 24.

Prime factorisation of 18 = 2 × 3 × 3

Prime factorisation of 24 = 2 × 2 × 2 × 3

Common factors of 18 and 24 = 2 × 3 = 6

HCF (18, 24) = 6

(ii) 51, 85

Prime factorisation of 51 = 3 × 17

Prime factorisation of 85 = 5 × 17

Common factors of 51 and 85 = 17

HCF (51, 85) = 17

(iii) 61, 76

Prime factorisation of 61 = 1 × 61

Prime factorisation of 76 = 2 × 2 × 19 × 1

Common factors of 61 and 76 = 1

HCF (61, 76) = 1

(iv) 84, 120

Prime factorisation of 84 = 2 × 2 × 3 × 7

Prime factorisation of 120 = 2 × 2 × 2 × 3 × 5

Common factors of 84 and 120 = 2 × 2 × 3

HCF (84, 120) = 12

(v) 27, 45, 81

Prime factorisation of 27 = 3 × 3 × 3

Prime factorisation of 45 = 3 × 3 × 5

Prime factorisation of 81 = 3 × 3 × 3 × 3

Common factors of 27, 45, 81 = 3 × 3 = 9

HCF (27, 45, 81) = 9

(vi) 45, 55, 95

Prime factorisation of 45 = 3 × 3 × 5

Prime factorisation of 55 = 5 × 11

Prime factorisation of 95 = 5 × 19

Common factors of 45, 55, 95 = 5

HCF (45, 55, 95) = 5

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