Sarthaks APP
0 votes
in Physics by (38.1k points)

A myopic adult has a far point at 0.1 m. His power of accomodation is 4 diopters. (i) What power lenses are required to see distant objects? (ii) What is his near point without glasses? (iii) What is his near point with glasses? (Take the image distance from the lens of the eye to the retina to be 2 cm.)

1 Answer

+1 vote
by (63.6k points)
selected by
Best answer

(i) Let the power at the far point be Pf for the normal relaxed eye.

With the corrective lens the object distance at the far point is . The power required is

The effective power of the relaxed eye with glasses is the sum of the eye and that of the glasses Pg.

(ii) His power of accommodation is 4 diopters for the normal eye. Let the power of the normal eye for near vision be Pn.

Then 4 = Pn – Pf or Pn = 64 D.

Let his near point be xn, then

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.