When 3 coins are tossed together,
Total no. of possible outcomes = 8 {HHH, HHT, HTH, HTT, THH,THT, TTH, TTT}
(i) Probability of an event = (No. of favorable outcomes)/(Total no. of possible outcomes)
Let E ⟶ event of getting exactly two heads
No. of favourable outcomes = 3 {HHT, HTH, THH}
Total no. of possible outcomes = 8
P(E) = 3/8
(ii) E ⟶ getting at least 2 Heads
No. of favourable outcomes = 4 {HHH, HHT, HTH, THH}
Total no. of possible outcomes = 8
P(E) = 4/8 = 1/2
(iii) E⟶ getting at least one Head & one Tail
No. of favourable outcomes = 6 {HHT, HTH, HTT, THH, THT, TTH}
Total no. of possible outcomes = 8
P(E) = 6/8 = 3/4
(iv) E ⟶ getting no tails
No. of favourable outcomes = 1 {HHH}
Total no. of possible outcomes = 8
P(E) = 1/8
