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In an estimation of sulphur by Carius method, 0.468 of an organic sulphur compound gave 0.668 g of barium sulphate. Find the percentage of sulphur in the compound.

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Percentage of sulphur 

\(\frac{32}{233}\times\frac{Mass\,of\,barium\,sulphate}{Mass\,of\,compound}\) x 100

\(\frac{32}{233}\times\frac{(0.668\,g)}{(0.468\,g)}\) x 100 = 19.60%

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